Đáp án:
d) Bậc 11
Giải thích các bước giải:
\(\begin{array}{l}
A = - \dfrac{2}{3}.\left( { - \dfrac{3}{4}} \right).\left( { - 1} \right).{x^{2 + 2}}.{y^{1 + 1}}\\
= - \dfrac{1}{2}{x^4}{y^2}\\
\to HS: - \dfrac{1}{2}\\
Biến:{x^4}{y^2}\\
Bậc:4 + 2 = 6\\
B = \dfrac{3}{{25}}{y^2}.{\left( { - \dfrac{4}{3}x} \right)^2}.\left( { - {y^3}} \right)\\
= \dfrac{3}{{25}}.\dfrac{{16}}{9}.\left( { - 1} \right).{x^2}.{y^{2 + 3}}\\
= - \dfrac{{16}}{{75}}{x^2}{y^5}\\
\to HS: - \dfrac{{16}}{{75}}\\
Biến:{x^2}{y^5}\\
Bậc:2 + 5 = 7\\
D = \dfrac{{11}}{{12}}{y^6}.\left( { - \dfrac{1}{{33}}{x^3}} \right).{x^2}\\
= - \dfrac{1}{{36}}{x^5}{y^6}\\
\to HS: - \dfrac{1}{{36}}\\
Biến:{x^5}{y^6}\\
Bậc:5 + 6 = 11
\end{array}\)
