1)
Các phản ứng xảy ra:
\(2{H_2}S + 3{O_2}\xrightarrow{{{t^o}}}2S{O_2} + 2{H_2}O\)
\(S + {O_2}\xrightarrow{{{t^o}}}S{O_2}\)
\(S{O_2} + B{r_2} + 2{H_2}O\xrightarrow{{}}{H_2}S{O_4} + 2HBr\)
\(Fe + {H_2}S{O_4}\xrightarrow{{}}FeS{O_4} + {H_2}\)
2)
Phản ứng xảy ra:
\(Zn + {H_2}S{O_4}\xrightarrow{{}}ZnS{O_4} + {H_2}\)
Ta có:
\({n_{Zn}} = \frac{{13}}{{65}} = 0,2{\text{ mol = }}{{\text{n}}_{ZnS{O_4}}} = {n_{{H_2}}}\)
\( \to {V_{{H_2}}} = 0,2.22,4 = 4,48{\text{ lít}}\)
\({m_{ZnS{O_4}}} = 0,2.(65 + 32 + 16.4) = 32,2{\text{ gam}}\)
