$\displaystyle \begin{array}{{>{\displaystyle}l}} BD=\sqrt{17^{2} +17^{2}} =17\sqrt{2}\\ \Rightarrow OD=\frac{1}{2} BD=\frac{17\sqrt{2}}{2}\\ Xét\ \Delta SOD\ vuông\ tại\ O\ có:\\ SO=v=\sqrt{SD^{2} -OD^{2}} =\sqrt{32^{2} -\frac{289}{2}} \approx 29,656 \end{array}$