Đáp án:
b) 45,36 kg
c) 44,46 kg
Giải thích các bước giải:
a)
\[C{H_2}OH - {\left( {CHOH} \right)_4} - CHO + 2AgN{O_3} + 3N{H_3} + {H_2}O \to C{H_2}OH - {\left( {CHOH} \right)_4} - COON{H_4} + 2Ag + 2N{H_3}N{O_3}\]
b)
\[\begin{gathered}
{n_{{C_6}{H_{12}}{O_6}}} = \dfrac{{37,8}}{{180}} = 0,21mol \Rightarrow {n_{Ag}} = 2{n_{{C_6}{H_{12}}{O_6}}} = 0,42mol \hfill \\
\Rightarrow {m_{Ag}} = 0,42.108 = 45,36kg \hfill \\
\end{gathered} \]
c)
\[\begin{gathered}
H = 85\% \Rightarrow {n_{{C_6}{H_{12}}{O_6}(tt)}} = \dfrac{{0,21}}{H} = 0,247mol \hfill \\
\Rightarrow {m_{{C_6}{H_{12}}{O_6}(tt)}} = 0,247.180 = 44,46kg \hfill \\
\end{gathered} \]
