Ta có: `5x = 3y`
`=> x/3 = y/5`
Đặt `x/3= y/5= k`
`=> x= 3k y= 5k`
Thay `x= 3k; y= 5k` vào `A` ta được
`A= (8(3k)^2 + 3(5k)^2 - 2(3k)(5k))/(10(3k)^2 - 3(5k)^2)`
`A= (8. 9k^2 + 3. 25k^2 - 2.15k^2)/(10. 9k^2 - 3.25k^2)`
`A= (72k^2 + 75k^2 - 30k^2)/(90k^2 - 75k^2)`
`A= ((72 + 75 - 30)k^2)/((90-75)k^2)`
`A= (117k^2)/(15k^2)`
`A= 117/15`
`A= 39/5`
Vậy `A= 39/5`