Đáp án:
\({V_{{H_2}}} = 0,224{\text{ lít;}}{{\text{V}}_{{H_2}S}} = 2,24{\text{ lít}}\)
\({m_{Fe}} = 0,56{\text{ gam;}}{{\text{m}}_{FeS}} = 8,8{\text{ gam}}\)
Giải thích các bước giải:
Phản ứng xảy ra:
\(Fe + 2HCl\xrightarrow{{}}FeC{l_2} + {H_2}\)
\(FeS + 2HCl\xrightarrow{{}}FeC{l_2} + {H_2}S\)
Hỗn hợp khí gồm \(H_2;H_2S\)
Ta có:
\({n_{{H_2}}} + {n_{{H_2}S}} = \frac{{2,464}}{{22,4}} = 0,11{\text{ mol}}\)
Cho hỗn hợp khí qua \(Pb(NO_3)_2\)
\(Pb{(N{O_3})_2} + {H_2}S\xrightarrow{{}}PbS + 2HN{O_3}\)
Ta có:
\({n_{PbS}} = \frac{{23,9}}{{207 + 32}} = 0,1{\text{ mol = }}{{\text{n}}_{{H_2}S}}\)
\( \to {n_{{H_2}}} = 0,11 - 0,1 = 0,01{\text{ mol}}\)
\( \to {V_{{H_2}}} = 0,01.22,4 = 0,224{\text{ lít;}}{{\text{V}}_{{H_2}S}} = 0,1.22,4 = 2,24{\text{ lít}}\)
\({n_{Fe}} = {n_{{H_2}}} = 0,01{\text{ mol;}}{{\text{n}}_{FeS}} = {n_{{H_2}S}} = 0,1{\text{ mol}}\)
\( \to {m_{Fe}} = 0,01.56 = 0,56{\text{ gam;}}{{\text{m}}_{FeS}} = 0,1.(56 + 32) = 8,8{\text{ gam}}\)
