$A=\frac{x+2√x+1}{√x+1}+\frac{x+1}{√x-1}-√x$
$~~~=\frac{(√x)^2+2√x+1}{√x+1}+\frac{(√x)^2-1}{√x-1}-√x$
$~~~=\frac{(√x+1)^2}{√x+1}+\frac{(√x+1)(√x-1)}{√x-1}-√x$
$~~~=√x+1+√x-1-√x$
$~~~=√x+2$
$Vậy:~A=√x+2$
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