`n_{Al}=\frac{2,7}{27}=0,1(mol)`
`n_{Mg}=\frac{2,4}{24}=0,1(mol)`
`n_{S}=\frac{1,6}{32}=0,05(mol)`
BTe:
$\mathop{Al}\limits^{0}\to \mathop{Al}\limits^{+3}+3e$
$\mathop{Mg}\limits^{0}\to \mathop{Mg}\limits^{+2}+2e$
$\mathop{S}\limits^{+6}+2e\to \mathop{S}\limits{+4}$
$\mathop{S}\limits^{+6}+6e\to \mathop{S}\limits^{0}$
Ta có:
`3n_{Al}+2n_{Mg}=2n_{SO_2}+6n_S`
`<=> 3.0,1+2.0,1=2n_{SO_2}+6.0,05`
`<=> n_{SO_2}=0,1(mol)`
`=> V_{SO_2}=0,1.22,4=2,24(l)`
Bảo toàn nguyên tố:
`n_{H_2SO_4}=n_{MgSO_4}+n_{Al_2(SO_4)_3}+n_{SO_2}+3n_{S}`
`=> n_{H_2SO_4}=0,1+0,05+0,1+0,15=0,4(mol)`
`V_{H_2SO_4}=\frac{n}{V}=\frac{0,4}{4}=0,1(l)`
