$\frac{x}{2}+x+\frac{x}{3}+x+x+ \frac{x}{4}=3\frac{5}{6}$
$x×\frac{1}{2}+x+x×\frac{1}{3}+x+x+x×\frac{1}{4}=\frac{23}{6}$
$x×(\frac{1}{2}+1+\frac{1}{3}+1+1+\frac{1}{4})=\frac{23}{6}$
$x×\frac{49}{12}=\frac{23}{6}$
$x =\frac{23}{6}:\frac{49}{12}$
$x =\frac{23}{6}×\frac{12}{49}$
$x =\frac{46}{49}$