\(\dfrac{1}{2}.x+\dfrac{1}{3}.\left(x-2\right)=\dfrac{1}{4}\)
\(\dfrac{1}{2}x+\dfrac{1}{3}x-\dfrac{1}{3}.2=\dfrac{1}{4}\)
\(\dfrac{1}{2}x+\dfrac{1}{3}x-\dfrac{2}{3}=\dfrac{1}{4}\)
\(\dfrac{1}{2}x+\dfrac{1}{3}x=\dfrac{1}{4}+\dfrac{2}{3}\)
\(\left(\dfrac{1}{2}+\dfrac{1}{3}\right)x=\dfrac{3}{12}+\dfrac{8}{12}\)
\(\left(\dfrac{3}{6}+\dfrac{2}{6}\right)x=\dfrac{11}{12}\)
\(\dfrac{5}{6}x=\dfrac{11}{12}\)
\(x=\dfrac{11}{12}:\dfrac{5}{6}\)
\(x=\dfrac{11}{10}\)
Vậy x = \(\dfrac{11}{10}\)
