Theo đề bài, ta có:
\(\left\{\begin{matrix}(x+1)yz=xyz+1\\x(y+1)z=xyz+2\\xy(z+1)=xyz+8\end{matrix}\right.\)
\(\left{\begin{matrix}xyz+yz=xyz+1\\xyz+xz=xyz+2\\xyz+xy=xyz+8\end{matrix}\right.\)
`=>` \(\left\{\begin{matrix}yz=1\\xz=2\\xy=8\end{matrix}\right.\)
`=> yz. xz. xy = 1. 2. 8`
`=> x^2. y^2. z^2 = 16`
`=> (xyz)^2 = (+-4)^2`
`=> xyz = +-4`
Vậy `xyz = 4` hoặc `xyz = -4`