Giải hệ phương trình: \(\left\{ \begin{array}{l}8x - y = 6\\{x^2} - y = - 6\end{array} \right..\)
A.\(S = \left\{ {\left( {6;\,\,42} \right)} \right\}.\)
B.\(S = \left\{ {\left( {6;\,\,42} \right),\,\,\left( {2;\,\,10} \right)} \right\}.\)
C.\(S = \left\{ {\left( {6;\,\,2} \right),\,\,\left( {2;\,\,10} \right)} \right\}.\)
D.\(S = \left\{ {\left( {6;\,\,42} \right),\,\,\left( {12;\,\,10} \right)} \right\}.\)
A.\(S = \left\{ {\left( {6;\,\,42} \right)} \right\}.\)
B.\(S = \left\{ {\left( {6;\,\,42} \right),\,\,\left( {2;\,\,10} \right)} \right\}.\)
C.\(S = \left\{ {\left( {6;\,\,2} \right),\,\,\left( {2;\,\,10} \right)} \right\}.\)
D.\(S = \left\{ {\left( {6;\,\,42} \right),\,\,\left( {12;\,\,10} \right)} \right\}.\)
Loga
Hóa Học lớp 12
