Em tham khảo nha :
\(\begin{array}{l}
{n_{C{O_2}}} = \dfrac{{30,49}}{{22,4}} = 1,36mol\\
{m_{KOH}} = \dfrac{{2073,156 \times 13,56}}{{100}} = 281,12g\\
{n_{KOH}} = \dfrac{{281,12}}{{56}} = 5,02mol\\
T = \frac{{{n_{KOH}}}}{{{n_{C{O_2}}}}} = \dfrac{{5,02}}{{1,36}} = 3,69\\
\Rightarrow\text{Phản ứng tạo ra 1 muối} {K_2}C{O_3}\\
2KOH + C{O_2} \to {K_2}C{O_3} + {H_2}O\\
{n_{{K_2}C{O_3}}} = {n_{C{O_2}}} = 1,36mol\\
{m_{{K_2}C{O_3}}} = 1,36 \times 138 = 187,68g
\end{array}\)