Đáp án:
`n^2+n+1 vdots n+3`
`<=>n^2-2n+3n-6+7 vdots n+3`
`<=>n(n-2)+3(n-2)+7 vdots n+3`
`<=>(n+3)(n-2)+7 vdots n+3`
`<=>7 vdots n+3` do `(n-2)(n+3) vdots n+3`
`<=>n+3 in Ư(7)={+-1,+-7}`
`<=>n in {-2,-4,4,-10}`.
Vậy `n in {-2,-4,4,-10}` thì `n^2+n+1 vdots n+3`