Lời giải:
e) `8^{x+1}=4^9`
`=> (2^3)^{x+1}=(2^2)^{9}`
`=> 2^{3(x+1)}=2^{2*9}`
`=> 2^{3(x+1)}=2^18`
`=>3(x+1)=18`
`=>x+1=6`
`=>x=5`
Vậy `x=5`
g) `2(x-3)^2-37=-5`
`=> 2(x-3)^2=32`
`=> (x+3)^2=16`
`=>`\(\left[ \begin{array}{l}x+3=\sqrt{16} = 4\\x+3=-\sqrt{16}=-4\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}x=4-3=1\\x+3=-4-3=-7\end{array} \right.\)
Vậy `x \in {1; -7}`
