Đáp án:
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`A = (4^{10} × 8^{12})/(2^{20} × 16^8)`
`↔ A = ( (2^2)^{10} × (2^3)^{12})/(2^{20} × (2^4)^8)`
`↔ A = (2^{20} × 2^{36})/(2^{20} × 2^{32})`
`↔ A = 2^{56}/2^{52}`
`↔ A = 2^4/1`
`↔ A= 16`
Vậy `A = 16`
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`B = (3^9 × 5^{10})/(9^4 × 25^5)`
`↔ B = (3^9 × 5^{10})/( (3^2)^4 × (5^2)^5)`
`↔ B = (3^9 × 5^{10})/(3^8 × 5^{10})`
`↔ B = (3 × 1)/(1 × 1)`
`↔ B = 3`
Vậy `B=3`
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`C = (27^4 × 8^4)/(9^5 × 2^8)`
`↔ C = ( (3^3)^4 × (2^3)^4)/( (3^2)^5 × 2^8)`
`↔ C = (3^{12} × 2^{12})/(3^{10} × 2^8)`
`↔ C = (3^2 × 2^4)/(1 × 1)`
`↔ C = 9 × 16`
`↔ C = 144`
Vậy `C=144`
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`D = (2^{10} × 27)/(6^4 ×8^3)`
`↔ D = (2^{10} × 3^3)/( (2 × 3)^4 × (2^3)^3)`
`↔ D = (2^{10} × 3^3)/(2^4 × 3^4 × 2^9)`
`↔ D = (2^{10} × 3^3)/(2^{13} × 3^4)`
`↔ D = (1 × 1)/(2^3 × 3)`
`↔ D = 1/(8 × 3)`
`↔ D = 1/24`
Vậy `D=1/24`
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`E = (4^2 × 3^4)/(2^2 × 6^2)`
`↔ E = ( (2^2)^2 × 3^4)/(2^2 × (2×3)^2)`
`↔ E = (2^4 × 3^4)/(2^2 × 2^2 × 3^2)`
`↔ E = (2^4 × 3^4)/(2^4 × 3^2)`
`↔ E = (1 ·× 3^2)/(1×1)`
`↔ E = 3^2`
`↔ E = 9`
Vậy `E=9`
