Giúp mình với ạ, cần gấp:))) thanks

trangdoann04

2 năm trước

Loga Sinh Học lớp 12

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Trangtruong

Đáp án:

`a>=0`

`\sqrt{a/6}+\sqrt{(2a)/3}+\sqrt{(3a)/2}`

`=\sqrta/\sqrt6+\sqrt{2a}/\sqrt3+\sqrt{3a}/\sqrt2`

`=\sqrt{6a}/6+\sqrt{6a}/3+\sqrt{6a}/2`

`=(\sqrt{6a}+2\sqrt{6a}+3\sqrt{6a})/6`

`=(6\sqrt{6a})/6=\sqrt{6a}.`

Vote (0) Phản hồi (0) 2 năm trước

nguyenthiyenminh2002

Đáp án + Giải thích các bước giải:

`sqrt(a/6)+sqrt((2a)/3)+sqrt((3a)/2)`

`=sqrt(a)/(sqrt6)+(sqrt(2a))/(sqrt3)+(sqrt(3a))/sqrt2`

`=sqrt(a)/(sqrt2*sqrt3)+(sqrt(2)*sqrta)/(sqrt3)+(sqrt3*sqrta)/(sqrt2)`

`=sqrt(a)/(sqrt2*sqrt3)+(sqrt2*sqrta*sqrt2)/(sqrt2*sqrt3)+(sqrt3*sqrta*sqrt3)/(sqrt2*sqrt3)`

`=(sqrta+2sqrta+3sqrta)/(sqrt2*sqrt3)=((1+2+3)sqrta)/(sqrt6)=(6sqrta)/(sqrt6)`

`=(6sqrta*sqrt6)/(sqrt6*sqrt6)=(6sqrt(6a))/6=sqrt(6a)`

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