Đáp án:
1. A = $\frac{6^3+ 3 . 6^2+ 3^3}{-13}$
= $\frac{2^3. 3^3+3 . 2^2.3^2.3^4}{-13}$
= $\frac{3^3.8+3^3.4+3^3.1}{-13}$
= $\frac{3^3.(8+4+1)}{-13}$
= $\frac{3^3.13}{-13}$
=$3^{3}$ . 1
= -27
2. $\frac{13 . 87+42}{13.88+29}$ - $\frac{115.89+3}{115.88-118}$
= $\frac{13.(88-1)+42}{13.88+29}$ $\frac{13.88-13+42}{13.88+29}$ - $\frac{115.88+118}{115.88+118}$
= $\frac{13.88+29}{13.88+29}$ - $\frac{115.88+118}{115.88+118}$
= 1 - 1 = 0