`d)-1+|x-5/6|=1/2`
`|x-5/6|=1/2-(-1)`
`|x-5/6|=1/2+1`
`|x+5/6|=3/2`
`⇒`\(\left[ \begin{array}{l}x+\dfrac{5}{6}=\dfrac{3}{2}\\x+\dfrac{5}{6}=\dfrac{-3}{2}\end{array} \right.\)
`⇒`\(\left[ \begin{array}{l}x=\dfrac{3}{2}-\dfrac{5}{6}\\x=\dfrac{-3}{2}-\dfrac{5}{6}\end{array} \right.\)
`⇒`\(\left[ \begin{array}{l}x=\dfrac{2}{3}\\x=\dfrac{-7}{3}\end{array} \right.\)
Vậy `x=2/3` hoặc `x=-7/3`
`e)x+5/8x-12/16x=1`
`x(1+5/8-12/16)=1`
`x. 7/8=1`
`x=1 : 7/8`
`x=1 . 8/7`
`x=8/7`
Vậy `x=8/7`
`f)(x+1/2)^2-1/3=6/9`
`(x+1/2)^2=6/9+1/3`
`(x+1/2)^2=1`
`(x+1/2)^2=1^2`
`⇒`\(\left[ \begin{array}{l}x+\dfrac{1}{2}=1\\x+\dfrac{1}{2}=-1\end{array} \right.\)
`⇒`\(\left[ \begin{array}{l}x=1-\dfrac{1}{2}\\x=-1-\dfrac{1}{2}\end{array} \right.\)
`⇒`\(\left[ \begin{array}{l}x=\dfrac{1}{2}\\x=\dfrac{-3}{2}\end{array} \right.\)
Vậy `x=1/2` hoặc `x=-3/2`
