Đáp án:
Bài 1: Tính
a, `3^2 . 1/243 . 81^2 . 1/(3^3)`
`= 3^2 : 3^5 . 3^8 : 3^3`
`= 3^2= 9`
b, `(4 . 2^5) : (2^3 . 1/16)`
` = 2^7 : 2`
` = 2^6`
Bài 2: Tính
a, `(2^-1 + 3^-1) : (2^-1 - 3^-1) + (2^-1. 2^0) : 2^3`
`= (1/2 + 1/3) : (1/2 - 1/3) + 1/2 : 8`
`= 5/6 : 1/6 +1/16`
`= 5 + 1/16 = 81/16`
b, `(-1/3)^-1 - (-6/7)^0 + (1/2)^2 : 2`
= -3 - 1 + 1/4 : 2`
`= -4 + 1/8`
`= -31/8`
Đề ra số hơi to nên mình sửa
c, `[(0,1)^2] + [(1/7)^-1]^2 . 1/49 . [(2^2)^3 : 2^5]`
`= 1/100 + 49 . 1/49 . 2`
`= 1/100 + 2`
`= 201/100`