Đáp án + Giải thích các bước giải:
`(2-x)^{4}=(x-2)^{2}`
`<=>(x-2)^{4}-(x-2)^{2}=0`
`<=>(x-2)^{2}[(x-2)^{2}-1]=0`
`<=>` \(\left[ \begin{array}{l}(x-2)^{2}=0\\(x-2)^{2}-1=0\end{array} \right.\)
`<=>` \(\left[ \begin{array}{l}x-2=0\\(x-2)^{2}=1\end{array} \right.\)
`<=>` \(\left[ \begin{array}{l}x=2\\x-2=±1\end{array} \right.\)
`<=>` \(\left[ \begin{array}{l}x=2\\x=3\\x=1\end{array} \right.\)
Vậy `x∈{1;2;3}`
