1. B= $x^{5}$ -15$x^{4}$ + 16$x^{3}$ - 29$x^{2}$ +13$x^{}$
Vì x=14 ⇒ x+1=15; x+2=16; 2x+1 = 29; x-1=13
⇒ B= $x^{5}$ -(x+1)$x^{4}$ + (x+2)$x^{3}$ - (2x+1)$x^{2}$ +(x-1)$x^{}$
= $x^{5}$ - $x^{5}$ -$x^{4}$ +$x^{4}$ + 2$x^{3}$ - 2$x^{3}$ - $x^{2}$ + $x^{2}$ -$x^{}$
= -$x^{}$
= -14
2. 2 (5x-8) - 3 (4x-5) = 4 (3x-4) + 11
10x -16 -12x +15 = 12x -16 +11
-14x = -4
x = $\frac{2}{7}$
Vậy x = $\frac{2}{7}$