Đáp án:
$\begin{array}{l}
e)\left( {\dfrac{5}{7}.0,6 - 5:3\dfrac{1}{2}} \right).\left( {40\% - 1,4} \right).{\left( { - 2} \right)^3}\\
= \left( {\dfrac{5}{7}.\dfrac{3}{5} - 5:\dfrac{7}{2}} \right).\left( {\dfrac{2}{5} - \dfrac{7}{5}} \right).\left( { - 8} \right)\\
= \left( {\dfrac{3}{7} - \dfrac{{10}}{7}} \right).\left( { - 1} \right).\left( { - 8} \right)\\
= \left( { - 1} \right).8\\
= - 8\\
f)4\dfrac{1}{2}:\left( {2,5 - 3\dfrac{3}{4}} \right) + {\left( {\dfrac{{ - 1}}{2}} \right)^2}\\
= \dfrac{9}{2}:\left( {\dfrac{5}{2} - \dfrac{{15}}{4}} \right) + \dfrac{1}{4}\\
= \dfrac{9}{2}:\dfrac{{ - 5}}{4} + \dfrac{1}{4}\\
= \dfrac{9}{2}.\dfrac{{ - 4}}{5} + \dfrac{1}{4}\\
= \dfrac{{ - 67}}{{20}}\\
g)\dfrac{{13}}{{15}}.0,25.3 + \left( {\dfrac{8}{{15}} - 1\dfrac{{19}}{{60}}} \right):1\dfrac{{23}}{{24}}\\
= \dfrac{{13}}{{15}}.\dfrac{1}{4}.3 + \dfrac{{ - 47}}{{60}}.\dfrac{{24}}{{47}}\\
= \dfrac{{13}}{{20}} + \dfrac{{ - 2}}{5}\\
= \dfrac{1}{4}\\
h)\left( {\dfrac{7}{4}.\dfrac{{ - 4}}{5} + \dfrac{7}{2}.\dfrac{{ - 1}}{5}} \right).50\% - 0,1\\
= \left( {\dfrac{7}{2}.\dfrac{{ - 2}}{5} + \dfrac{7}{2}.\dfrac{{ - 1}}{5}} \right).\dfrac{1}{2} - 0,1\\
= \dfrac{7}{2}.\dfrac{{ - 2 - 1}}{5}.\dfrac{1}{2} - \dfrac{1}{{10}}\\
= \dfrac{{ - 21}}{{20}} - \dfrac{1}{{10}}\\
= \dfrac{{ - 23}}{{20}}\\
i)\left( {2\dfrac{1}{3} + 3\dfrac{1}{2}} \right).0,2 + 25\% \\
= \dfrac{{35}}{6}.\dfrac{1}{5} + \dfrac{1}{4}\\
= \dfrac{7}{6} + \dfrac{1}{4} = \dfrac{{17}}{{12}}\\
j)\dfrac{4}{7} + \dfrac{5}{6}:5 - 0,375.{\left( { - 2} \right)^2}\\
= \dfrac{4}{7} + \dfrac{1}{6} - \dfrac{3}{8}.4\\
= \dfrac{4}{7} + \dfrac{1}{6} - \dfrac{3}{2}\\
= \dfrac{{ - 16}}{{21}}
\end{array}$
