Đáp án:
$\begin{array}{l}
Do:Am//Bn\\
\Leftrightarrow \widehat {xAm} = \widehat {AHB}\left( {\text{đồng vị}} \right)\\
Do:Ax//By\\
\Leftrightarrow \widehat {AHB} = \widehat {yBn}\left( {so\,le\,trong} \right)\\
\Leftrightarrow \widehat {xAm} = \widehat {yBn}\\
Vậy\,\widehat {xAm} = \widehat {yBn}
\end{array}$