Hỗn hợp A gồm BaO, FeO, Al2O3. Hoà tan A trong lượng dư nước, được dung dịch à và phần không tan B. Sục khí CO2 dư bào dung dịch D, phản ứng tạo kết tủa. Cho khí CO dư đi qua B nung nóng thu được chất rắn E. Cho E tác dụng với dung

Oanhnhao

2 năm trước

Hỗn hợp A gồm BaO, FeO, Al2O3. Hoà tan A trong lượng dư nước, được dung dịch à và phần không tan B. Sục khí CO2 dư bào dung dịch D, phản ứng tạo kết tủa. Cho khí CO dư đi qua B nung nóng thu được chất rắn E. Cho E tác dụng với dung dịch NaOH dư, thấy tan một phần còn lại chất rắn G. Hoà tan hết G trong một lượng dư dung dịch H2SO4 loãng rồi cho dung dịch thu được tác dụng với dung dịch KMnO4. Xác định các chất . Viết các phương trình phản ứng xảy ra.

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nguyenkhanhvan595

Đáp án:

Giải thích các bước giải:

– Hoà tan hỗn hợp A vào lượng dư nước có các phản ứng:
`BaO + H2O = Ba(OH)2`
`Ba(OH)2 + Al2O3 = Ba(AlO2)2 + H2O`
Dung dịch D là Ba(AlO2)2
Phần không tan B: FeO và Al2O3 còn dư (Do E tan một phần trong dd NaOH).
– Sục khí CO2 dư vào D:
`Ba(AlO2)2 + 2CO2 + 4H2O = 2Al(OH)3? + Ba(HCO3)2`
– Cho khí CO dư qua B nung nóng có phản ứng sau:
`FeO + CO = Fe + CO2`
Chất rắn E: Fe và Al2O3
– Cho E tác dụng với dung dịch NaOH dư:
`Al2O3 + 2NaOH = 2NaAlO2 + H2O`
Chất rắn G: Fe.
– Cho G tác dụng với dung dịch H2SO4
`Fe + H2SO4 = FeSO4+ H2`
và dung dịch thu được tác dụng với dung dịch KMnO4
`2KMnO4 + 10FeSO4+ 8H2SO4 = 2MnSO4+ 5Fe2(SO 4)3 + K2SO 4+ 8H2O`

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thok2003

Dung dịch \(B\) chứa \(Ba(AlO_2)_2\)

\(B\) gồm \(FeO\) và \(Al_2O_3\) dư

\(E\) gồm \(Fe;Al_2O_3\)

\(G\) là \(Fe\)

Các phản ứng xảy ra:

\(BaO + {H_2}O\xrightarrow{{}}Ba{(OH)_2}\)

\(Ba{(OH)_2} + A{l_2}{O_3}\xrightarrow{{}}Ba{(Al{O_2})_2} + {H_2}O\)

\(Ba{(Al{O_2})_2} + 2C{O_2} + 4{H_2}O\xrightarrow{{}}Ba{(HC{O_3})_2} + 2Al{(OH)_3}\)

\(FeO + CO\xrightarrow{{{t^o}}}Fe + C{O_2}\)

\(A{l_2}{O_3} + 2NaOH\xrightarrow{{}}2NaAl{O_2} + {H_2}O\)

\(Fe + {H_2}S{O_4}\xrightarrow{{}}FeS{O_4} + {H_2}\)

\(10FeS{O_4} + 2KMn{O_4} + 8{H_2}S{O_4}\xrightarrow{{}}5F{e_2}{(S{O_4})_3} + {K_2}S{O_4} + 2MnS{O_4} + 8{H_2}O\)

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