$\text{Đáp án+Giải thích các bước giải:}$
$a) |5x-4|=|x+2|$
$TH1: 5x-4=x+2 ⇔ 4x=6 ⇔ x=$ $\dfrac{3}{2}$
$TH2: 5x-4=-x-2 ⇔ 6x=2 ⇔ x=$ $\dfrac{1}{3}$
$b) |2x-3|-|3x+2|=0$
$⇔ |2x-3|=|3x+2|$
$TH1: 2x-3=3x+2 ⇔ x=-5$
$TH2: 2x-3=-3x-2 ⇔ 5x=1 ⇔ x=$ $\dfrac{1}{5}$
$c) |2x+3|=|4x-3|$
$TH1: 2x+3=4x-3 ⇔ 2x=6 ⇔ x=3$
$TH2: 2x+3=3-4x ⇔ x=0$
$d) |7x+1|-|5x+6|=0$
$⇔ |7x+1|=|5x+6|$
$TH1: 7x+1=5x+6 ⇔ 2x=5 ⇔ x=$ $\dfrac{5}{2}$
$TH2: 7x+1=-5x-6 ⇔ 12x=-7 ⇔ x=$ $\dfrac{-7}{12}$
