Đáp án:
Giải thích các bước giải:
$b,$
$\dfrac{9^2.9^3}{3^{10}}.2018$
$=\dfrac{9.9.9.9.9}{3^{10}}.2018$
$=\dfrac{3^2.3^2.3^2.3^2.3^2}{3^{10}}.2018$
$=\dfrac{3^{10}}{3^{10}}.2018=2018$
$d,$
$\dfrac{3^{27}}{9^5.3^{16}}$
$=\dfrac{3^{27}}{9.9.9.9.9.3^{16}}$
$=\dfrac{3^{27}}{3^2.3^2.3^2.3^2.3^2.3^{16}}$
$=\dfrac{3^{27}}{3^{26}}$
$=3$