Đáp án:
Giải thích các bước giải:
$\text{1/ 2x²-4x+2}$
$\text{=x²+x²-2x-2x+1+1}$
$\text{=(x²-2x+1)+(x²-2x+1)}$
$\text{=(x-1)²+(x-1)²}$
$\text{=2(x-1)²}$
$\text{2/ 3x³-6x²y+3xy²}$
$\text{=3x(x²-2xy+y²)}$
$\text{=3x(x-y)²}$
$\text{3/ 5x²+10xy+5y²}$
$\text{=5(x²+2xy+y²)}$
$\text{=5(x+y)²}$
$\text{4/ 2x²-8}$
$\text{=2(x²-4)}$
$\text{=2(x-2)(x+2)}$
$\text{5/ 8x²-18}$
$\text{=2(4x²-9)}$
$\text{=2(2x-3)(2x+3)}$
$\text{6/ 8x²-4y}$
$\text{=4(2x²-y)}$
