Đáp án:
$\begin{array}{l}
- \dfrac{1}{3}{x^5}{y^2}:\left( { - 2xy} \right) - \left( {{x^2} + 2x + 4} \right):\left( {x + 1} \right)\\
= \dfrac{{{x^5}{y^2}}}{{3.2xy}} - \dfrac{{{x^2} + x + x + 1 + 3}}{{x + 1}}\\
= \dfrac{{{x^4}y}}{6} - \dfrac{{x\left( {x + 1} \right) + x + 1 + 3}}{{x + 1}}\\
= \dfrac{1}{6}{x^4}y - \dfrac{{\left( {x + 1} \right)\left( {x + 1} \right) + 3}}{{x + 1}}\\
= \dfrac{1}{6}{x^4}y - \left( {x + 1} \right) - \dfrac{3}{{x + 1}}
\end{array}$
