Đáp án:
Giải thích các bước giải:
a, $\frac{1}{2}$ -( $\frac{1}{3}$+ $\frac{1}{10}$)
= $\frac{15}{30}$ - ( $\frac{10}{30}$+ $\frac{3}{30}$)
= $\frac{15}{30}$ - $\frac{13}{30}$
= $\frac{2}{30}$
= $\frac{1}{15}$
b, $\frac{1}{12}$-(- $\frac{1}{6}$- $\frac{1}{4}$)
= $\frac{1}{12}$-(- $\frac{2}{12}$- $\frac{3}{12}$)
= $\frac{1}{12}$- (- $\frac{5}{12}$)
= $\frac{6}{12}$
= $\frac{1}{2}$
c, $\frac{1}{2}$- $\frac{-1}{3}$+ $\frac{1}{23}$+ $\frac{1}{6}$
= ($\frac{1}{2}$- $\frac{-1}{3}$+ $\frac{1}{6}$)++ $\frac{1}{23}$
=1+ $\frac{1}{23}$
= $\frac{24}{23}$
