Đáp án:
\( {m_{dd\;{{\text{H}}_2}S{O_4}}} = 150{\text{ gam}}\)
\({m_{N{a_2}S{O_4}}} = 42,6{\text{ gam}}\)
Giải thích các bước giải:
Phản ứng xảy ra:
\(2NaOH + {H_2}S{O_4}\xrightarrow{{}}N{a_2}S{O_4} + 2{H_2}O\)
Ta có:
\({n_{NaOH}} = 0,3.2 = 0,6{\text{ mol}}\)
\( \to {n_{{H_2}S{O_4}}} = {n_{N{a_2}S{O_4}}} = \frac{1}{2}{n_{NaOH}} = 0,3{\text{ mol}}\)
\( \to {m_{{H_2}S{O_4}}} = 0,3.98 = 29,4{\text{ gam}}\)
\( \to {m_{dd\;{{\text{H}}_2}S{O_4}}} = \frac{{29,4}}{{19,6\% }} = 150{\text{ gam}}\)
\({m_{N{a_2}S{O_4}}} = 0,3.(23.2 + 96) = 42,6{\text{ gam}}\)