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taehyungiebangtan95
2 năm trước
Cho tam giác ABC vuông tại A có đường cao AH. Gọi E, F lần lượt là hình chiếu vuông góc của H lên AB, AC. CMR: a) $AB^{3}$ = BE . $BC^{2}$ b) $\sqrt[3]{BE^{2}}$ + $\sqrt[3]{CF^{2}}$ = $\sqrt[3]{BC^{2}}$
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