Đáp án:
$a)2a^2-b^2\\ b)6b^2-7ab\\ c)3b^2+2x^2-7bx\\ d)32x^2-30a^2-5ax$
Giải thích các bước giải:
$a)(2a-b)(b+4a)+2a(b-3a)\\ =2ab+8a^2-b^2-4ab+2ab-6a^2\\ =2a^2-b^2\\ b)(3a-2b)(2a-3b)-6a(a-b)\\ =6a^2-9ab-4ab+6b^2-6a^2+6ab\\ =6b^2-7ab\\ c)5b(2x-b)-(8b-x)(2x-b)\\ =10bx-5b^2-(16bx-8b^2-2x^2+bx)\\ =10bx-5b^2-16bx+8b^2+2x^2-bx\\ =3b^2+2x^2-7bx\\ d)2x(a+15x)+(x-6a)(5a+2x)\\ =2ax+30x^2+5ax+2x^2-30a^2-12ax\\ =32x^2-30a^2-5ax$