|$\frac{5}{2}$ x-3|-$\frac{7}{2}$ =$\frac{1}{4}$
=>|$\frac{5}{2}$ x-3|=$\frac{1}{4}$+$\frac{7}{2}$
=>|$\frac{5}{2}$ x-3|=$\frac{15}{4}$
=>\(\left[ \begin{array}{l}\frac{5}{2} x-3=\frac{15}{4}\\\frac{5}{2} x-3=-\frac{15}{4}\end{array} \right.\)
=>\(\left[ \begin{array}{l}\frac{5}{2} x=\frac{15}{4}+3\\\frac{5}{2} x=-\frac{15}{4}+3\end{array} \right.\)
=>\(\left[ \begin{array}{l}\frac{5}{2} x=\frac{27}{4}\\\frac{5}{2} x=-\frac{3}{4}\end{array} \right.\)
=>\(\left[ \begin{array}{l} x=\frac{27}{4}:\frac{5}{2}\\x=-\frac{3}{4}:\frac{5}{2}\end{array} \right.\)
=>\(\left[ \begin{array}{l} x=\frac{27}{10}\\x=-\frac{-3}{10}\end{array} \right.\)
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