a, bc(b+c)+ca(c-a)-ab(a+b)
= bc(b+c)+ac² - a²c - a²b -ab²
= bc(b+c)- a²(b+c) - a (b+c)(b-c)
= (b+c)( bc + a² - ab - ac)
= (b+c) ( c ( b+a ) - a ( a+ b) )
= ( b + c ) ( b + a ) ( c - a)
b, x² - x + y² - y
= (x² - y² ) + (-x - y)
=( x + y)( x - y) - ( x + y)
= ( x + y ) ( x- y - 1)
Đáp án:
$\displaystyle \begin{array}{{>{\displaystyle}l}} a.( b+c)( b+a)( c-a) \ \\ b.( x-y-1)( x+y) \end{array}$
Giải thích các bước giải:
$\displaystyle \begin{array}{{>{\displaystyle}l}} a.bc( b+c) +ca( c-a) -ab( a+b)\\ =bc( b+c) +ac^{2} -a^{2} c-a^{2} b-ab^{2}\\ =bc( b+c) -a^{2}( b+c) -a( b+c)( b-c)\\ =\left( bc-a^{2} -a( b-c)\right)( b+c)\\ =( b+c)( c( b+a) -a( a+b))\\ =( b+c)( b+a)( c-a)\\ b.\ x^{2} -x-y^{2} -y\\ =\left( x^{2} -y^{2}\right) -( x+y)\\ =( x-y)( x+y) -( x+y)\\ =( x-y-1)( x+y) \end{array}$
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Viết đoạn văn cho đề sau : Phải chăng chỉ có những điều ngọt ngào mới làm nên yêu thương
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Giải hộ mình với , hứa vote 5*, mình đang cần gấp ạ
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