Đáp án:
$\dfrac{{{k_2}}}{{{k_1}}} = 16$
Giải thích các bước giải:
Ta có:
$\begin{array}{l}
{A_1} = \Delta {l_{o1}} = \dfrac{{{m_1}g}}{{{k_1}}}\\
{A_2} = \Delta {l_{o2}} = \dfrac{{{m_2}g}}{{{k_2}}}\\
\dfrac{{{W_1}}}{{{W_2}}} = \dfrac{{\dfrac{1}{2}{k_1}{A_1}^2}}{{\dfrac{1}{2}{k_2}{A_2}^2}} = \dfrac{{{m_1}^2{k_2}}}{{{m_2}^2{k_1}}} = 4\\
\Leftrightarrow \dfrac{{{m_1}^2}}{{{{\left( {2{m_1}} \right)}^2}}}.\dfrac{{{k_2}}}{{{k_1}}} = 4\\
\Leftrightarrow \dfrac{{{k_2}}}{{{k_1}}} = 16
\end{array}$