a)(2x-1)(2y+1)=2
⇒(2x-1)(2y+2)=1.2=(-1).(-2)=2.1=(-2).(-1)
TH1:(2x-1)(2y+1)=1.2
=>x=1 ; y=1/2 (kTM)
TH2:(2x-1)(2y+1)=(-1).(-2)
=>x=0;y=-3/2(ktm)
TH3:(2x-1)(2y+1)=2.1
=>x=3/2;y=0(ktm)
Vậy(x;y)= Ф
b)(4x+1)(y-3)=5
⇒(4x+1)(y-3)=1.5=5.1=(-1)(-5)=(-5).(-1)
Th1:(4x+1)(y-3)=1.5
⇒x=0;y=8
th2:(4x+1)(y-3)=5.1
⇒x=1;y=4
TH3:(4x+1)(y-3)=(-1)(-5)
⇒x=-2/4;y=-2(ktm)
TH4:(4x+1)(y-3)=(-5)(-1)
=>x=-6/4;y=-2(KTM)
vậy (x;y)=(0,8);(1,4)
