Gọi $M(x;y)\in (P')$
$\begin{array}{l} {T_{\overrightarrow v }}\left( M \right) = M'\left( {x';y'} \right)\\ \Rightarrow \left\{ \begin{array}{l} x' = x + 0\\ y' = y + 1 \end{array} \right. \Rightarrow \left\{ \begin{array}{l} x' = x\\ y = y' - 1 \end{array} \right.\\ \Rightarrow M \in \left( {P'} \right):y = - {x^2} - 2x + 1\\ \Leftrightarrow y' - 1 = - x{'^2} - 2x' + 1\\ \Leftrightarrow y' = - x{'^2} - 2x + 2 \end{array}$
Chọn $D$