Đáp án:
`A<B`
Giải thích các bước giải:
`A=12(5^2+1)(5^4+1)...(5^128+1)`
`=1/2 . 24(5^2+1)(5^4+1)...(5^128+1)`
`=1/2 . (5^2-1)(5^2+1)(5^4+1)...(5^128+1)`
`=1/2 . (5^4-1)(5^4+1)...(5^128+1)`
`=1/2 . (5^8-1)(5^8+1)...(5^128+1)`
`=1/2 . (5^16-1)(5^16+1)...(5^128+1)`
`=1/2 . (5^32-1)(5^32+1)...(5^128+1)`
`=1/2 . (5^64-1)(5^64+1)(5^128+1)`
`=1/2 . (5^128-1)(5^128+1)`
`=1/2 . (5^256-1) < 5^256-1 = B`
Vậy `A<B`