a) Vì OCB là tam giác đều nên BC = BO = BM = R
`=>` `\hat{OCB}` = $90^o$ `=>` MC là tiếp tuyến của ( O ; R)
b) Ta có `OM^2` = `OC^2` + `MC^2`
`=>` `MC^2` = `3R^2`
Đáp án:
Giải thích các bước giải:
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Giúp em câu này ạ , em cảm ơn rất nhiều câu 1 thui nha anh chị
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