`a) 3(x-2)+2 >=1-2(x+3)`
`<=> 3x-6+2>=1-2x-6`
`<=>3x+2x>=1-6+6-2`
`<=>5x>=-1`
`=> x>=-1/5 . Vậy : x >= -1/5`
`b) 2- (3(x+1))/8 < (x-1)/4`
`<=> (16-3x-3)/8 - (x-1)/4<0`
`<=>(13-3x)/8 - (x-1)/4<0`
`<=>(13-3x-2(x-1))/8<0`
`<=>(13-3x-2x+2)/8<0`
`<=>(15-5x)/8<0 (1)`
`Do 8>0 . Từ (1) => 15-5x<0`
`<=> -5x<-15`
`=> x>3 . Vậy : x > 3`
