b, 41-$2^{x+1}$ = 9
⇔ $2^{x+1}$ = 32
⇔ $2^{x+1}$ = $2^{5}$
⇔ x+1 = 5
⇔ x = 4
h, $5^{2x-3}$ - 2.$5^{2}$ = $5^{2}$ .3
⇔ $5^{2x-3}$ = $5^{2}$ .5
⇔ $5^{2x-3}$ = $5^{3}$
⇔ 2x-3 = 3
⇔ 2x = 6
⇔ x = 3
c, $3^{2x-4}$ - $x^{0}$ = 8
⇔$3^{2x-4}$ - 1 = 8
⇔$3^{2x-4}$ = 9
⇔$3^{2x-4}$ = $3^{2}$
⇔ 2x-4 = 2
⇔ 2x = 6
⇔ x = 3
CHO MK CTLHN NHA^-^
