`x^2=x^5`
`⇔x^2-x^5=0`
`⇔x^2(1-x^3)=0`
`⇔`\(\left[ \begin{array}{l}x^2=0\\1-x^3=0\end{array} \right.\)
`⇔`\(\left[ \begin{array}{l}x=0\\x=1\end{array} \right.\)
Vậy `x∈{0;1}`
Đáp án:
Giải thích các bước giải:
`x^2 = x^5`
`→ x^5 - x^2 = 0`
`→ x^2 . ( x^3 - 1 ) = 0`
`→ x^2 = 0` hoặc `x^3 - 1 = 0`
`→ x = 0` hoặc `x^3 = 1`
`→ x = 0` hoặc `x = 1`
Vậy `x ∈ { 0; 1 }`
Vẽ anime or calli : '' I'm Boy '' P/s : Người ơi gặp gỡ làm chi Trăm năm biết có duyên gì hay không. ?
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Giúp mình giải bài này với! Mình cảm ơn nhìu ạ! Ném một vật thẳng đứng lên cao với vận tốc ban đầu 10m/s từ độ cao 5m so với mặt đất. Lấy g=10m/s^2. a) Tính độ cao cực đại b) Tính độ cao của vật khi vận tốc giảm đi một nửa so với vận tốc đầu c) Vật có vận tốc bao nhiêu khi độ cao bằng 3/2 độ cao ban đầu d) Tính vận tốc khi vật vừa chạm đất e) Trong giây cuối cùng, động năng của vật tăng thêm một lượng là bao nhiêu?
1 you lost the keys. Have you found them?(that) -> have 2. They said something.Did you hear it? (What) Did you hear ...
Giúp mình câu 1,2,3,4,5 vote 50 cần gấp
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vẽ lô gô D3K44 đô lương 3 hứa vote 5 sao
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Mn giúp mình 1 câu này với,mình cảm ơn
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