$\text{Ta có:}$
`4/x = -3/{y+1} = 1/-2`
$\Rightarrow$ `-3/{y+1} = 1/-2`
$\Rightarrow$ `1(y+1) = (-3) . (-2)`
$\Rightarrow$ `y + 1 = 6`
$\Rightarrow$ `y = 6 - 1`
$\Rightarrow$ `y = 5`
----------------------------
$\text{Ta có:}$
`4/x = -3/{y + 1} (1)`
$\text{Thay y = 5 vào (1) ta có:}$
$\Rightarrow$ `4/x = -3/{5 + 1}`
$\Rightarrow$ `4/x = -3/6`
$\Rightarrow$ `4/x = -1/2`
$\Rightarrow$ `x . (-1) = 4 . 2`
$\Rightarrow$ `- x = 8`
$\Rightarrow$ ` x = - 8`
$\text{Vậy x = -8 , y = 5}$
$\Rightarrow$ $\text{Chọn 2}$
