Em tham khảo nha :
\(\begin{array}{l}
2Al + 6HCl \to 2AlC{l_3} + 3{H_2}\\
Zn + 2HCl \to ZnC{l_2} + {H_2}\\
{n_{{H_2}}} = \dfrac{{6,72}}{{22,4}} = 0,3mol\\
{n_{HCl}} = 2{n_{{H_2}}} = 0,6mol\\
{V_{HCl}} = \dfrac{{0,6}}{2} = 0,3l = 300ml\\
3AgN{O_3} + AlC{l_3} \to 3AgCl + Al{(N{O_3})_3}\\
2AgN{O_3} + ZnC{l_2} \to 2AgCl + Zn{(N{O_3})_2}\\
{n_{C{l^ - }}} = {n_{HCl}} = 0,6mol\\
{n_{AgCl}} = {n_{C{l^ - }}} = 0,6mol\\
{m_{AgCl}} = 0,6 \times 143,5 = 86,1g
\end{array}\)