Đáp án:
Giải thích các bước giải:
$a) 2^3+3.(-\dfrac{1}{2})^0.(\dfrac{1}{2})^2.4+[(-2):\dfrac{1}{2}]$
$=8+3.1.\dfrac{1}{4}.4+[(-2).2]$
$=8+3.1+(-4)$
$=8+3+(-4)$
$=7$
$b) (2^2.\dfrac{2^3}{4^4}.16)^{15}:(\dfrac{2^6}{16^2})^{10}$
$=(2^2.\dfrac{2^3}{(2^2)^4}.2^4)^{15}:(\dfrac{2^6}{(2^4)^2})^{10}$
$=(\dfrac{2^2.2^3.2^4}{2^8})^{15}:(\dfrac{2^6}{2^8})^{10}$
$=(\dfrac{2^9}{2^8})^{15}:(\dfrac{1}{2})^{10}$
$=2^{15}:\dfrac{1}{2^{10}}$
$=2^{15}.2^{10}$
$=2^{25}$