7 - 2(x-3)² = 5
2(x-3)² = 7 - 5
2(x-3)² = 2
(x-3)² = 2 : 2
(x-3)² = 1
(x-3)² = ±1²
=> \(\left[ \begin{array}{l}x-3=1\\x-3=-1\end{array} \right.\)
=> \(\left[ \begin{array}{l}x=1+3\\x=-1+3\end{array} \right.\)
=> \(\left[ \begin{array}{l}x=4\\x=2\end{array} \right.\)