Đáp án:
$\begin{array}{l}
a)Dkxd:x \ge 0\\
\sqrt x = 3\\
\Leftrightarrow x = {3^2}\\
\Leftrightarrow x = 9\left( {tmdk} \right)\\
Vậy\,x = 9\\
b)Dkxd:x \ge 0\\
\sqrt x = \sqrt 5 \\
\Leftrightarrow x = {\left( {\sqrt 5 } \right)^2}\\
\Leftrightarrow x = 5\left( {tmdk} \right)\\
Vậy\,x = 5\\
c)Dkxd:x \ge 0\\
\sqrt x = 0\\
\Leftrightarrow x = 0\left( {tmdk} \right)\\
Vậy\,x = 0
\end{array}$