a)
`7x(2x-3) =0`
`=>` \(\left[ \begin{array}{l}7x =0 \\2x -3 =0\end{array} \right.\)
`=>` \(\left[ \begin{array}{l}x=0\\x=\dfrac{3}{2}\end{array} \right.\)
Vậy `x \in { 0 ; 3/2}`
b)
`1/3x +2/5(x+1) =0`
`=> 1/3x+ 2/5x +2/5 =0`
`=> 11/15x = -2/5`
`=> x = -2/5 : 11/15`
`=> x = -2/5 . 15/11`
`=> x = -6/11`
Vậy `x = -6/11`