`a.`
`m_{NaCl}=n.M=0,05.58,5=2,925(g)`
`b.`
`n_{N_2}=V/(22,4)=(2,24)/(22,4)=0,1(mol)`
`m_{N_2}=n.M=0,1.28=2,8(g)`
`c.`
`500(ml)=0,5(l)`
`n_{NaOH}=V_{dd}.C_M=0,5.1=0,5(mol)`
`m_{NaOH}=n.M=0,5.40=20(g)`
`\text{___________________________________}`
Đáp án:
`a.m_{NaCl}=2,925(g)`
`b.m_{N_2}=2,8(g)`
`c.m_{NaOH}=20(g)`